2 spaceships are intertwined in a galactic fight; each have a limited number of lasers to fire. One pilot fires one sixth of their lasers and are left with 40 shots left; how many lasers did that pilot start with?
Solution:
x - x/6 = 40
(try x = 6)
6 - 6/6 = 6-1 = 5
since 40/5 = 8, we can try x = 48
48 - 48/6 = 48 - 8 = 40
So the pilot initially had 48 shots
Nice! I like your Star Wars style story, and you've explained the method clearly too.
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